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Sum or difference of an odd and even number is odd. Sum and difference of two odd numbers is Even. Sum, product or difference of two even numbers yields an even number. However, multiplying by a positive number, the inequality does not change. By multiplying by -2, the inequality has changed. However, if X is a fraction between 0 and 1, any higher (n greater than or equal to powers of X i.e. pk (1-p)n-kĢ3) Standard Deviation = Mean + or – 1 SD = 68%Ģ5) Watch for |X|, GMAT likes questions involving modulus.Ģ6) In general, X^2 is greater than X. If n= 5, r = 3, so required ways = 7C2 = 21.Ģ0) no of ways in which n things can be divided among r persons so that each of them receive at least 1 = (n-1)C(r-1)=4C2=6.Ģ1) Bi-nominal dist = nPk = nCk. I am not sure about how/ if it extends to trapezoid, but it extends a to a Rhombus: d1^2 + d2^2 = 4a^2ĭiagonal is the longest distance in a rectangular box.ĭ = sqrt (10^2 + 10^2 + 5^2) = sqrt (225) = 15.ġ9) No of ways in which n things can be divided among r persons so that each of them can receive 0 or more is = (n+r-1)C(r-1) ways. Thus area = 12 piġ0) Area of the Pyramid = 1/3 * base S * heightġ1) Acute triangle =Ěll angles less than 90 degreesġ2) Obtuse angle = One angle is 90 degree or more than 90 degreeġ3) Scalene triangle = None of the sides are equalġ4) Size of the Right Angle Triangles =ē0 : 60 : 90 (1 : √3 : 2)ġ5) Trapezoid = A quadrilateral with two opposite sides parallel.ġ6) Parallelogram =Ě quadrilateral with parallel opposite sides.ġ7) Rhombus = A quadrilateral with all equal sides and parallel opposite sides.ġ8) A parallelogram with sides 14 and 18 and 1 diagonal of 16, other diagonal =d1^2 + d2^2 =2(a^2+b^2) =28, where d1 and d2 are two diagonals, a and b are two sides. Therefore in this case, a = 6 and radius of the circle = 2 sqrt(3). Where, S=(a+b+c)/3Ĩ) Area of the equilateral triangle: (S^2)ĩ) Equilateral triangle inscribed in a circle, r = a/sqrt(3). Thus area = 12 piĦ) Diagonal is the longest distance in a rectangular box.ĭiagonal D = sqrt(L^2 + W^2 + H^2) = D = sqrt(10^2 + 10^2 + 5^2) D = sqrt(225) D = 15įinding the slope of a line with two points (x1,y1) (x2,y2) = (y2-y1)/(x2-x1)ĭistance between two points = sqrtĭistance of a point (x1, y1) from a line (ax + by + c = 0) : (ax1+by1+c)/ sqrt(a^2+b^2)ħ) Area of the triangle: Sqrt. If a side, a = 6, then radius of the circle = 2 sqrt(3). The radius of a circle in which an equilateral triangle inscribed = a/sqrt(3). Sign Up to access the content listed below.Zero is divisible by every integer (except 0), since remainder of 0/k = 0 To identify which of the three possible sections you were assigned (Easy, Medium, or Difficult), just check the beginning of Question#1 in Section#5 and compare it to the description listed below.
#Gre powerprep 2 quant solution h is the midpoint plus#
Section 3: (Question 1) $0 \lt x \lt y \lt 1$ Quantity A: $(y-x)$…ĭepending on how you do in the first Quantitative reasoning section(Section#3) of the POWERPREP PLUS Online test, your next section will be adaptive, meaning the level of difficulty will change. Video Explanations: POWERPREP PLUS Online TEST 2 The playlists below organize my video explanations to the computer based PowerPrep Plus Online Practice test 1 that is part of the official GRE POWERPREP PLUS Online tests.